The sum of digits of a number is 23 and it gives rem 7 when divided by 11.Find the remainder when divided by 33...Anybody give a soln....but no trial and error please

Question

Answer 1

The number is of the form 11k+7
The number cannot be a two digit number because maximum sum of the digits in a two digit number is 18
The minimum 3 digit number whose sum of digits is 23 is 599. The next number is 689, which is of the form 11k+7
689 mod 33 = 29

Answer 2

The number is of the form 11k+7
The number cannot be a two digit number because maximum sum of the digits in a two digit number is 18
The minimum 3 digit number whose sum of digits is 23 is 599. The next number is 689, which is of the form 11k+7
689 mod 33 = 29

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The sum of digits of a number is 23 and it gives rem 7 when divided by 11.Find the remainder when divided by 33...Anybody give a soln....but no trial and error please