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2 years, 11 months ago
2 years, 11 months ago
Hi Shivanshi,
Let the quadratic equation be (x-a)(x-b) = 0
Given, a = 17
We can find sum of the coefficients by substituting x with 1, i.e.
Sum of coefficients = (1-a)(1-b)
As it is mentioned that roots differ by less than 17, b can take values from 1 to 33
Required sum = (1-17)(1-1) + (1-17)(1-2) + ............ + (1-17)(1-33) = (16)(16)(33) = 8448
Hope this helps!
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