Venugopal
10y ago
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Venugopal
10y ago
Pv Aaditya 10y ago
Hi Venugopal,
Powers of natural numbers follow a particular pattern as far as the last digit is concerned:
$$2^{4k+1}$$ ends in 2, $$2^{4k+2}$$ ends in 4, $$2^{4k+3}$$ ends in 8, $$2^{4k+4}$$ ends in 6. Similarly, $$12^{4k+1}$$ ends in 2, $$12^{4k+2}$$ ends in 4, and so on
$$3^{4k+1}$$ ends in 3, $$3^{4k+2}$$ ends in 9, $$3^{4k+3}$$ ends in 7, $$3^{4k+4}$$ ends in 1
$$4^{2k+1}$$ ends in 4, $$4^{2k+2}$$ ends in 6
Powers of 5 always end in 5
...
and so on
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