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9Â years, 6Â months ago
9Â years, 6Â months ago
Euler of 101 = 100
So, 7^100 mod 101 = 1
7 * 7^99 mod 101 = 1
Let 7^99 mod 101 = k
=> 7k mod 101 = 1
=> 7k = 101p + 1
p = 2 satisfies for k = 29
So, remaninder = 29
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