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Quadratic Equations

Formula

Let D denote the discriminant $$b^{2}-4ac$$. Hence, depending on the sign and value of D, nature of the roots would be as follows:

  • D < 0 β†’ Complex (imaginary) roots
  • D = 0 β†’ Real, equal roots: x = βˆ’b/2a
  • D > 0, perfect square β†’ Real, rational, unequal
  • D > 0, not a perfect square β†’ Real, irrational, unequal (conjugate surds)

If roots are irrational or complex, they always occur in conjugate pairs

Formula

The General Quadratic equation will be in the form of a$$x^{2}$$+b$$x$$+c = 0

The values of β€˜x’ satisfying the equation are called the roots of the equation.

The value of roots, p and q = $$\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$$

The sum of the roots = p+q = $$\dfrac{-b}{a}$$

Product of roots = p*q = $$\dfrac{c}{a}$$

If c and a are equal then the roots are reciprocal to each other.

If b = 0, then the roots are equal and are opposite in sign.

If roots are given : (x-a)(x-b)=0 => $$x^2 - (a+b)x + ab = 0$$

If sum s and product p of roots are given: $$x^2 - sx + p = 0$$


    Formula

    If $$A_{n}X^{n}$$ + $$A_{n-1}X^{n-1}$$ + ... + $$A_{1}X$$ + $$A_{0}$$ = 0 and n>=3, then 

    • Sum of the roots = $$-A_{n-1}/ A_{n}$$

    • Sum of roots taken two at a time = $$A_{n-2}/ A_{n}$$

    • Sum of roots taken three at a time = $$-A_{n-3}/ A_{n}$$ and so on

    • Product of the roots =$$(-1)^nA_0/A_n$$

    Ex: For a cubic axΒ³+bxΒ²+cx+d=0 with roots p,q,r:

    • p+q+r = βˆ’b/a

    • pq+qr+rp = c/a

    • pqr = βˆ’d/a

    Formula

    Minimum and maximum values of $$ax^{2}+bx+c=0$$ :

    • If a > 0: minimum value = $$\frac{4ac - b^2}{4a}$$ and occurs at x = $$\frac{-b}{2a}$$

    • If a < 0: maximum value = $$\frac{4ac - b^2}{4a}$$ and occurs at x = $$\frac{-b}{2a}$$

    Formula

    Signs of the roots: Let P be the product of roots, and S be their sum

    • P > 0, S > 0 : Both roots are positive

    • P > 0, S < 0 : Both roots are negative

    • P < 0, S > 0 : Numerical smaller root is negative, and the other root is positive

    • P < 0, S < 0 : Numerical larger root is negative, and the other root is positive

    Formula

    Finding a quadratic equation:

    • If roots are reciprocals of roots of equation $$ax^2 + bx + c = 0$$, then equation is $$cx^2 + bx + a = 0$$

    • If roots are k more than roots of $$ax^2 + bx + c = 0$$ then equation is $$a(y-k)^2 + b(y-k) + c = 0$$

    • If roots are k times roots of $$ax^2 + bx + c = 0$$ then equation is $$a(y/k)^2 + b(y/k) + c = 0$$

    • If roots are negatives of roots of axΒ²+bx+c=0, new equation is axΒ²βˆ’bx+c=0

    • If p and q are roots of axΒ²+bx+c=0, and we want a new equation whose roots are pΒ² and qΒ². The equation will be $$a^2x^2βˆ’(b^2βˆ’2ac)x+c^2=0$$

    Theory

    Descartes Rules : A polynomial equation with n sign changes can have a maximum of n positive roots. To find the maximum possible number of negative roots, find the number of positive roots of f(-x).

    An equation where highest power is odd must have at least one real root

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