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8 years, 9 months ago
Is there any trick to solve para jumbles?
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Solution: By Fermat's theorem as 24 and 7 are coprimes, remainder of 24^6 mod 7 =1. Hence,24^13 can be split up as 24^6* 24^6* 24 mod 7 = 1*1*3 mod 7 =3. Hence, remainder is 3. How is 24 mod 7 calculated here
Four unique even numbers are arranged in ascending order and the first two are decreased by 50%, while the last two are increased by 50%. If the original sum of the 4 numbers was 162, the new sum can be?In the solution it is mentioned that the last two numbers must be 4 greater than the first two. Why?
how much percentage from objective test and interview, will be added in final cutoff of joining for IBPS PO?
how much percentage from objective test and interview, will be added in final cutoff of joining ?
i want to know that what specific part or topics one have to cover to score good i gs?
I am basically from commerce field,so I cant understand geometry very well....what should I do to improve geometry?
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