## Ask a Question

Abhilasha Kamble
5 hours, 16 minutes ago

My Question is, why did they considered the shaded region as the whole First quadrant (with y axis as well) and not the intersection of those two lines: -x+y=3 and x+y=6

Abhilasha Kamble
5 hours, 17 minutes ago

My Question is, why did they considered the shaded region as the whole First quadrant (with y axis as well) and not the intersection of those two lines: -x+y=3 and x+y=6

yasir
16 hours, 33 minutes ago

some A are B, some B are C, All C are D.

conclusion:

some A are not D. I am unsure whether this conclusion is false.

Nikhil Rajpurohit

Yes , this condition is false because there is no connection between A & D, so all A can be D , that's why we can't say some A is not D.

0 Likes Posted 10 hours, 7 minutes ago
Charan dhingra
1 day, 6 hours ago

**ci= 5670 p= 6160 T= 8years**

sandeep Gautam
1 day, 18 hours ago

**ibps p.o. mock test series fee?**

Styles Tomilson Alima
1 day, 21 hours ago

how to tackle algebra ,geometry

pooja yadav
2 days, 5 hours ago

**A man can reach a certain place in 30hrs.if he reduces his speed by 1/15th, he covers 10km less in that time.find his speed.**

Karan Chaudhary
2 days, 7 hours ago

**At a particular time in the twenty first century there were seven bowlers in the Indian cricket team's list of 16 players short listed to play the next world cup. Statisticians discovered that that if you looked at the number of wickets taken by any of the 7 bowlers of the current Indian cricket team, the number of wickets taken by them had a strange property. The numbers were such that for any team selection of 11 players (having 1 to 7 bowlers) by using the number of wickets taken by each bowler and attaching coefficients of +1, 0, or -1 to each value available and adding the resultant values, any number from 1 to 1093 , both included could be formed. If we denote W1, W2, W3, W4, W5, W6 and W7 as the 7 values in the ascending order what could be the answer to the following questions :. Q1 Find the value of W1 + 2W2 + 3W3 + 4W4 + 5W5 + 6W6. Q2 : Find the index of the largest power of 3 contained in the product W1W2W3W4W5W6W7 . Q3 : If the sum of the seven coefficients is 0, find the smallest number that can be obtained.**