Sristhikumari008@gmail.com
1 week, 1 day ago

Can I use the package offline?

Shakya Mohapatra
1 week, 2 days ago

The price for complete cat package 2017 was 7500 day before yesterday. How come its 10.5k now?

Maruti Konduri
2 Likes Posted 1 week, 1 day ago

Hi Shakya,

The decreased price for Complete Cracku was during a super discount offer. It has ended now and Complete Cracku will cost the normal price is 10.5k+taxes ~ 12k.

sakshi gupta
1 week, 2 days ago

I

I am getting 32 answer because I considered

1. All six subjects failed(f) = 12

2. Exactly 5 failed = 0

3. Exactly 4 failed =0

4. Exactly 3 failed (c)=1

5. Exactly 2 failed= 0

6. Exactly 1 Failed = 45-13 = 32

please help me, where am I going wrong?

865x149

Prachi
1 week, 3 days ago

How can i get maximum efficiency in RC questions

suri
0 Likes Posted 1 week ago

Hi Prachi, have read cracku's article on how to tackle RC's ? If not check this How to tackle reading comprehension. Then it all comes to practicing it daily. Solve 3 or 4 RC's on Daily basis, by this you can improve a lot. Check this Reading comprehension tests

John Mccarthy
1 week, 6 days ago

Process?

Siva Hemanth
0 Likes Posted 1 week, 4 days ago

let the intersection points be a.b and the points at which circles touch the rectangle be c,b. center of rect be o. no consider the sector area acb. now remove the area of triangle is abo from this. this will give 1/4 th area of the shaded part.

total area will be 60

John Mccarthy
0 Likes Posted 1 week, 5 days ago

Say related to circles. Ellipse isnt under discussion

John Mccarthy
1 week, 6 days ago

What are the number of meetings when 3 runners are running on a circular track with speeds : a:b:c. in 1) Same direction

2) a,b runs in the same direction,c on the opposite direction

Siva Hemanth
0 Likes Posted 1 week, 4 days ago

if a<b<c then

for 1 it will be LCM of (b-a,c-a,c-b)

for 2 it will be LCM of (b-a,c+b,c+a)

Mohit Gera
1 week, 6 days ago

Please provide detailed solution of this question.

Siva Hemanth
0 Likes Posted 1 week, 6 days ago

for 1st question d option answer--> 5

2 nd question b option

are they correct?

Vignesh
2 weeks ago

how to apply the concept of "divisibility by 37" for the following question.

4 is written 3400 times side by side to give a big number i.e. 44444.........444(3400 digits). What is the remainder when divided by 37?

ajaz iqbal

the remainder will be 4.
444 is completely divisible by 37 hence 44444......4444(3n digits) will also be completely divisible by 37
444444.........44444((3n+1) times) will give a remainder of 4 upon dividing by 37
4444.......4444((3n+2)times) will give a remainder of 7 upon dividing by 37. since 44 gives a remainder of 7 upon dividing by 37.
since 3400 can be represented as 3n +1 i.e, 331133 +1 hence the remainder will be 4

0 Likes Posted 1 week, 4 days ago
moses kurapati

37*3 is 111
Given is 4444...(3400 times ) so write it as
4*11111...(3400 times )
now let us find a relation
I.e., 111*1001 is 111111( 6 1's) 111*1001001 is 111111111( 9 1's)
so we are getting no of 1's as 3 multiples.
so for 111....(3399) I.e. 4*(11111..1110+1)..
and 40*11111....3399 times+4
therefore the remainder will be 4.

0 Likes Posted 1 week, 6 days ago140 points

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Hi Srishti,

As of now the package is completely online, we are implementing offline features and they will go live in the coming days.