Question 94
Three parallel lines are cut by two transversals as shown in the given figure. If AB = 2 cm, BC = 4 cm and DE = 1.5 cm, then the length of EF is:
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Solution
AD is parallel to BE is parallel to CF
$$\ \frac{\ AB}{BC}\ =\ \ \frac{\ DE}{EF}$$ [Basic proportionality theorem]
$$\ \frac{\ 2}{4}\ =\ \ \frac{\ 1.5}{EF}$$
EF = 3 cm
B is the correct answer.
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