XAT 2011 Question 92

Question 92

Rakhal is looking for a field where he can graze his cow. He finds a local farmer, Gopal, who agrees to rent his field to Rakhal for Rs. 1000 a year. Rakhal finds a post in the field and ties his cow to the post with a 25 feet rope. After some months, Gopal tells Rakhal that he will build a shed with four walls on the field with the post as one of the corner posts. The shed would be 15 feet by 10 feet. Rakhal agrees but he realizes that this arrangement would reduce the available area for grazing. What should be the modified rent to compensate for this loss of grazing area if Rakhal has to keep the cow tied to the same post with the same rope?

Solution

Original area for grazing = $$\pi \times (25)^2$$

= $$625 \pi$$ sq. feet

After the shed (15 $$\times$$ 10 feet) is built, quarter of the area will be reduced.

=> New area = $$\frac{3}{4} \pi \times (25)^2 + \frac{1}{4}[\pi (10)^2 + \pi (15)^2]$$

= $$\frac{1875 \pi}{4} + \frac{325 \pi}{4}$$

= $$\frac{2200 \pi}{4} = 550 \pi$$


Now, original area corresponds to Rs. 1,000

=> $$625 \pi \equiv 1000$$

$$\therefore 550 \pi \equiv 1000 \times \frac{550}{625}$$

= $$Rs. 880$$



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