A thief is stopped by a policeman from a distance of 200 metres. When the policeman starts the chase, the thief also starts running. Assuming the speed of the thief as 8 km/hr and that of police man as 10 km/hr. How far the thief would have run, before he is over­taken?

Since the thief is escaping from the police man, thus they both are running in same direction.

Speed of thief = 8 km/hr and speed of policeman = 10 km/hr

=> Relative speed = 10 - 8 = 2 km/hr

Distance between them = 200 metres = 0.2 km

=> Time taken = $$\frac{distance}{speed}$$

= $$\frac{0.2}{2} = \frac{1}{10}$$ hr

$$\therefore$$ Distance covered by thief before he was caught = $$8 \times \frac{1}{10}$$

= 0.8 km = 800 metres