A thief is stopped by a policeman from a distance of 200 metres. When the policeman starts the chase, the thief also starts running. Assuming the speed of the thief as 8 km/hr and that of police man as 10 km/hr. How far the thief would have run, before he is overtaken?
Since the thief is escaping from the police man, thus they both are running in same direction.
Speed of thief = 8 km/hr and speed of policeman = 10 km/hr
=> Relative speed = 10 - 8 = 2 km/hr
Distance between them = 200 metres = 0.2 km
=> Time taken = $$\frac{distance}{speed}$$
= $$\frac{0.2}{2} = \frac{1}{10}$$ hr
$$\therefore$$ Distance covered by thief before he was caught = $$8 \times \frac{1}{10}$$
= 0.8 km = 800 metres
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