For the figure given below, find the value ( in degrees) of $$2\angle A+\angle B$$

Given : $$\angle$$ C = $$45^\circ$$ and AC = BC

=> $$\angle$$ A = $$\angle$$ B    [Angles opposite to equal sides]

Let $$\angle$$ A = $$x$$

To find : $$2\angle A+\angle B=3x=?$$

Solution : In $$\triangle$$ ABC,

=> $$\angle$$ A + $$\angle$$ B + $$\angle$$ C = $$180^\circ$$

=> $$x+x=180^\circ-45^\circ=135^\circ$$

=> $$x=\frac{135^\circ}{2}=67.5^\circ$$

$$\therefore$$ $$2\angle A+\angle B=3x=3\times67.5^\circ=202.5^\circ$$

=> Ans - (B)