If the numbers appeared on the two throws of a fair six faced die are $$\alpha$$ and $$\beta$$, then the probability that $$x^2 + \alpha x + \beta > 0$$, for all $$x \in \mathbb{R}$$, is

A

$$\dfrac{17}{36}$$

B

$$\dfrac{4}{9}$$

C

$$\dfrac{1}{2}$$

D

$$\dfrac{19}{36}$$