A straight line cuts off the intercepts OA = a and OB = b on the positive directions of x-axis and y-axis respectively. If the perpendicular from origin O to this line makes an angle of $$\frac{\pi}{6}$$ with positive direction of y-axis and the area of $$\triangle OAB$$ is $$\frac{98}{3}\sqrt{3}$$, then $$a^2 - b^2$$ is equal to:

A

$$\frac{392}{3}$$

B

196

C

$$\frac{196}{3}$$

D

98