Solution
Expression : $$(sinA-2sin^3A)/(2cos^3A-cosA)$$
= $$\frac{sinA}{cosA} \times \frac{1-2sin^2A}{2cos^2A-1}$$
$$\because$$ $$(sin^2A+cos^2A=1)$$
= $$tanA \times \frac{(sin^2A+cos^2A)-2sin^2A}{2cos^2A-(sin^2A+cos^2A)}$$
= $$tanA \times \frac{cos^2A-sin^2A}{cos^2A-sin^2A}$$
= $$tanA \times 1 = tanA$$
=> Ans - (D)
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