The length of two parallel sides of a trapezium are 18 m and 24 m. If its height is 12 m, then what is the area $$(in m^2)$$ of the trapezium ?
Sum of parallel sides = 18 + 24 = 42 m and height = 12 m
Area of trapezium = $$\frac{1}{2}\times h\times$$ (sum of parallel sides)
=Â $$\frac{1}{2}\times42\times12$$
= $$42\times6=252$$ $$m^2$$
=> Ans - (B)
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