The number of students of school D is more than the number of students of schools A and E together, by about

In A, 40% of students scored above 60% marks, the number of them being equal to 1160. Hence, the total number of students is 2900.

In B, 30% of students scored above 60% marks, the number of them being equal to 1170. Hence, the total number of students is 3900.

In C, 50% of students scored above 60% marks, the number of them being equal to 1170. Hence, the total number of students is 2340.

In D, 15% of students scored above 60% marks, the number of them being equal to 1200. Hence, the total number of students is 8000.

In E, 40% of students scored above 60% marks, the number of them being equal to 1600. Hence, the total number of students is 4000.

The number of students of schools A and E together = 2900+4000=6900.

The number of students of school D is more than the number of students of schools A and E together = 8000-6900=1100.

The percentage more is by $$\frac{1100}{6900}\cdot100=15.9$$

So, option A is the answer.