The cost prices of articles A and B are ₹1200 and ₹1600 respectively. The selling price of article A is ₹1380 and the total profit on selling both the articles is 25%. What is the profit percentage on selling of article B?

cost price (CP) , selling price(SP) , profit(P)

CP of A = 1200

CP of B = 1600

Total CP = 1200 + 1600 = 2800

SP of A = 1380

SP of B assume as 'x'

Total SP = 1380 + x

Total profit on selling both the articles is 25% = $$ \frac{25}{100} = \frac{1}{4} $$

p% = $$ \frac{SP - CP}{CP} \times 100 $$

Substituting values,

$$ \frac{1}{4} = \frac{1380 + x - 2800}{2800} $$

On solving we get x = 2120

SP of B = 2120

Therefore P% on selling article B = $$ \frac{2120 - 1600}{1600} \times 100 $$

                                                 = $$ \frac{520}{1600} \times 100 $$

                                                  = 32.5