Question 72

What is the highest number which when divides the numbers 1026, 2052 and 4102, leave remainders 2, 4 and 6 respectively?

Solution

Let's assume the highest number is 'y' when divides the numbers 1026, 2052 and 4102, leave remainders 2, 4 and 6 respectively.

So 1026-2 = 1024

2052-4 = 2048

4102-6 = 4096

Now we need to take the HCF of 1024, 2048 and 4096.

1024 = 1024

2048 = $$1024\times2$$

4096 = $$1024\times4$$

So the HCF for these = y = 1024

Create a FREE account and get:

Free SSC Study Material - 18000 Questions
230+ SSC previous papers with solutions PDF
100+ SSC Online Tests for Free

CAT Quant Questions | CAT Quantitative Ability

CAT Time And Work Questions CAT Averages Mixtures Alligations Questions CAT Geometry Questions CAT Coordinate Geometry Questions CAT Data Sufficiency Questions

CAT DILR Questions | LRDI Questions For CAT

CAT Special Charts Questions CAT Venn Diagrams Questions CAT DI Miscellaneous Questions CAT Truth Lie Concept Questions CAT Coins and Weights Questions

CAT Verbal Ability Questions | VARC Questions For CAT

CAT Critical Reasoning Questions CAT Verbal Ability Questions CAT Para Jumbles Questions CAT Odd One Out Questions CAT Miscellaneous Questions

Follow us on

Boost your Prep!

Download App