R and S start walking towards each other at 10 AM at the speeds of 3 km per hour and 4 km per hour respectively. They were initially 17.5 km apart. At what time do they meet?
Given, R and S are moving at the speeds of 3 kmph and 4 kmph respectively. And distance between them is 17.5 km
Relative speed = 3 + 4 = 7 kmph
Time taken for R and S to meet = $$\frac{17.5}{7}$$ = $$2.5$$ hours
They meet at (10 AM + 2.5 hours) = 12:30 PM
Hence, option D is the correct answer.
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