Dheeraj can cover a certain distance in 5 hours and 22 minutes by covering three-fourth of the distance at 5 km/h and rest at 6 km/h.Find the total distance covered by him.

Let's assume the total distance is '4d' km.

Dheeraj can cover a certain distance in 5 hours and 22 minutes by covering three-fourth of the distance at 5 km/h and rest at 6 km/h.

$$\frac{3d}{5}+\frac{d}{6}\ =\ 5\frac{22}{60}$$

$$\frac{3d}{5}+\frac{d}{6}\ =\ 5\frac{11}{30}$$

$$\frac{18d}{30}+\frac{5d}{30}\ = \frac{161}{30}$$

$$\frac{23d}{30} = \frac{161}{30}$$

23d = 161

d = 7

total distance covered by him = 4d

= $$4\times7$$

= 28 km