Question 7

Three natural numbers $$n_1$$, $$n_2$$, $$n_3$$ are taken. Let $$ n_{1} < n_{2} < n_{3} $$ and $$n_1 + n_2 + n_3 = 6$$. The value of $$n_3$$ is

Solution

The three natural numbers are different and increasing, so the smallest they can possibly be is 1, 2 and 3, and these already add up to 6. Any other set of three different natural numbers has a sum bigger than 6. So $$n_1 = 1$$, $$n_2 = 2$$, $$n_3 = 3$$ and the value of $$n_3$$ is 3.

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Three natural numbers $$n_1$$, $$n_2$$, $$n_3$$ are taken. Let $$ n_{1} < n_{2} < n_{3} $$ and $$n_1 + n_2 + n_3 = 6$$. The value of $$n_3$$ is

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