Question 68

If three numbers are in the ratio 2 : 3 : 5 and the twice of their sum is 200. The square of the largest of three numbers is:

Solution

If three numbers are in the ratio 2 : 3 : 5 and the twice of their sum is 200.

Let's assume three numbers are 2y, 3y and 5y.

2(2y+3y+5y) = 200

(2y+3y+5y) = 100

10y = 100

y = 10

square of the largest of three numbers = $$(5y)^2$$

= $$(5\times10)^2$$

= $$(50)^2$$

= 2500

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