Question 68
If three numbers are in the ratio 2 : 3 : 5 and the twice of their sum is 200. The square of the largest of three numbers is:
Solution
If three numbers are in the ratio 2 : 3 : 5 and the twice of their sum is 200.
Let's assume three numbers are 2y, 3y and 5y.
2(2y+3y+5y) = 200
(2y+3y+5y) = 100
10y = 100
y = 10
square of the largest of three numbers = $$(5y)^2$$
= $$(5\times10)^2$$
= $$(50)^2$$
= 2500
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