In an office, there are 216 tables and 264 chairs. If $$\frac{1}{6}$$ of the tables and $$\frac{1}{4}$$ of the chairs are broken then how many people can work in the office if each person requires one table and one chair?

In an office, there are 216 tables and 264 chairs. If $$\frac{1}{6}$$ of the tables and $$\frac{1}{4}$$ of the chairs are broken.

Remaining tables = 216 of $$(1-\frac{1}{6})$$ = 216 of $$\frac{5}{6}$$ = 180

Remaining chairs = 264 of $$(1-\frac{1}{4})$$ = 264 of $$\frac{3}{4}$$ = 198

In question, it is given that each person requires one table and one chair to work in the office. There are 180 tables and 198 chairs remaining. So we can say that 180 people can work in the office.