If $$p, q$$ and $$r$$ are three propositions, then which of the following combination of truth values of $$p$$, $$q$$ and $$r$$ makes the logical expression $$\{(p \vee q) \wedge ((\neg p) \vee r)\} \to ((\neg q) \vee r)$$ false?

A

$$p = T, q = F, r = T$$

B

$$p = T, q = T, r = F$$

C

$$p = F, q = T, r = F$$

D

$$p = T, q = F, r = F$$