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Question 66
Two trains, 130 and 110 metres long, are going in the same direction. The faster train takes one minute to pass the other completely. If they are moving in opposite directions, they pass each other completely in 3 seconds. What is the speed of the faster train?
Solution
Let speed of faster and slower train is 'x' m/sec and 'y' m/sec respectibvely.
Now,
130 + 110 = (x - y) * 60
x - y = 4
130 + 110 = (x + y) * 3
x + y = 80
Speed of faster train = $$\frac{4 + 80}{2} = 42$$ m/sec
