Sign in
Please select an account to continue using cracku.in
↓ →
$$a, b, c$$ are three positive numbers, such that, $$(a + b + c) = 20, a^2 + b^2 + c^2 = 152$$. The value of $$(ab + bc + ca)$$ is equal to:
$$(a + b + c)^{2}=a^2 + b^2 + c^2+2(ab+bc+ac)$$
$$20^{2}=a^2 + b^2 + c^2+2(ab+bc+ac)$$
$$400=152+2(ab+bc+ac)$$
$$(ab+bc+ac)=\frac{248}{2}=124$$
Create a FREE account and get:
Start your IIM journey with the right preparation and crack CAT 2026.
Educational materials for CAT preparation
Ask our AI anything
AI can make mistakes. Please verify important information.
AI can make mistakes. Please verify important information.
91- 6303239042
