E and F can do a work in 10 days. If E alone can do it in 30 days, F alone can do it in days.
E and F can do a work =10 daysÂ
E alone can do it =Â 30 days
total work = lcm (10,30) = 30
(E+ F)'s efficiency = $$\frac{work}{time}$$ =Â $$\frac{30}{10}$$ = 3
E' s efficiency =Â $$\frac{work}{time}$$ =Â $$\frac{30 }{30}$$ = 1
soÂ
F's efficiency = 3 - 1 = 2
so , F time taken =Â Â $$\frac{work}{time}$$ =$$\frac{30}{2}$$ = 15 days
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