It is given that $$\triangle$$ ABC and $$\triangle$$ DEF are equiangular triangles, thus corresponding angles are equal.

=> $$\triangle$$ ABC $$\sim\triangle$$ DEF

=> Ratio of perimeter = $$\frac{AB}{DE}=$$ $$\frac{BC}{EF}=$$ $$\frac{AC}{DF}$$ -------------(i)

Since, AL and DM are medians, => Ratio of perimeter of $$\triangle$$ ABC to $$\triangle$$ DEF = $$\frac{AL}{DM}$$ -----------(ii)

From, equations (i) and (ii), we get :

=> $$\frac{BC}{EF}=\frac{AL}{DM}$$

=> Ans - (B)