Question 6

An aeroplane takes off 30 minutes later than the scheduled time and in order to reach its destination 1500 km away in time, it has to increase its speed by 250 km/h from its usual speed. Find its usual speed.

Solution

$$time\ =\ \frac{dis\tan ce}{speed}$$

$$t1=\ \frac{1500}{S}$$

$$t2=\ \frac{1500}{S+250}$$

Given t1 - t2 = 1/2 hours

So, $$\frac{1500}{S}\ -\frac{1500}{S+250}=\frac{1}{2}$$

On solving S=750kmph

Create a FREE account and get:

SNAP Quant Questions | SNAP Quantitative Ability

SNAP Syllabus

SNAP Admit Card

SNAP Cutoffs

SNAP Eligibility Criteria

SNAP Exam Dates

SNAP Colleges List

SNAP Study Material

SNAP Registration

SNAP Result

SNAP Previous Year Papers

SNAP Crash Course

SNAP Mock Tests