The mass of NH$$_3$$ produced when $$131.8$$ kg of cyclohexane carbaldehyde undergoes Tollen's test is _____ kg. (Nearest Integer)
Molar mass of C $$= 12$$ g/mol, N $$= 14$$ g/mol, O $$= 16$$ g/mol

When an aldehyde undergoes oxidation with Tollen's reagent, the balanced chemical equation is:

From the stoichiometry of this reaction, 1 mole of aldehyde produces exactly 4 moles of ammonia (NH3)

• Cyclohexane carbaldehyde ($$C_{7}H_{12}O$$):
  Molar Mass $$=(7\times12)+(12\times1)+(1\times16)=84+12+16=112g/mol$$
• Ammonia ($$NH_3$$):
  Molar Mass $$= 14 + (3 × 1) = 17 g/mol$$

Given mass of cyclohexane carbaldehyde $$= 131.8 kg = 131800 g$$

According to the 1 : 4 stoichiometric ratio: