Question 58

The major product of the following reaction is:
CH$$_3$$CH = CHCO$$_2$$CH$$_3$$ $$\xrightarrow{\text{LiAlH}_4}$$

Name: The major product of the following reaction is: CH_3CH = CHCO_2CH_3 \\xrightarrow{\\text{LiAlH}_4}
Uploaded: 2026-05-19T14:48:39.404193+05:30
Duration: 1 min 27 s
Description: The major product of the following reaction is: CH_3CH = CHCO_2CH_3 \\xrightarrow{\\text{LiAlH}_4}

Solution

LiAlH4 is a strong reducing agent hence it reduces the the carbonyl group to -OH and since -OH and OMe are unstable staying on a single carbon -OMe leaves and forms MeOH and another Hydrogen is added to the -OH substituted carbon.

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The major product of the following reaction is:CH$$_3$$CH = CHCO$$_2$$CH$$_3$$ $$\xrightarrow{\text{LiAlH}_4}$$

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The major product of the following reaction is:
CH$$_3$$CH = CHCO$$_2$$CH$$_3$$ $$\xrightarrow{\text{LiAlH}_4}$$