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In the given figure there are three circles each of radius 1 cm touching each other and internally touching a larger circle. The radius of the larger circle is
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Radius of larger circle = PC + Circum Radius of $$\triangle{ABC}$$ [PC = Radius of smaller circle = 1 cm]
$$\triangle{ABC}$$ is equilateral triangle with side = 2 cm
Circum of an equilateral triangle = $$\frac{a}{\sqrt{3}} = \frac{2}{\sqrt{3}}$$
Radius of large circle = $$1 + \frac{2}{\sqrt{3}} = \frac{\sqrt{3} + 2}{\sqrt{3}} = \frac{3 + 2\sqrt{3}}{3}$$
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