Question 57
Weight of A is 20% more than weight of B, whose weight is 30% more than weight of C. By how much percent weight of A is more than weight of C?
Solution
Weight of B is 30% more than weight of C.
B = $$\frac{130}{100}\times$$C
Weight of A is 20% more than weight of B.
A = $$\frac{120}{100}\times$$B = $$\frac{120}{100}\times\frac{130}{100}\times$$C = $$\frac{156}{100}$$C
Required percentage = $$\frac{\frac{156}{100}C-C}{C}\times100$$
= $$\frac{56}{100}\times100$$
= 56%
Hence, the correct answer is Option B
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