If the sum of the interior angles of a regular polygon measures up to 1440 degrees, how many sides does the polygon have?
Let number of sides be $$n$$
Sum of interior angles = $$(n-2)\times180^\circ=1440^\circ$$
=> $$n-2=\frac{1440}{180}$$
=> $$n=8+2=10$$
=> Ans - (A)
Create a FREE account and get: