Question 51

Big Bang Theory cast wishes to find out the number of ways in which the word ASTRONAUT can be scrambled. They ﬁnd that the number of ways in which it can be put in an unscrambling puzzle is?

Solution

Number of letters in ASTRONAUT = 9

Here A and T are repeated twice.

So the number of ways of arrangement = $$\ \frac{\ 9!}{2!\times\ 2!}$$

= 90720

D is the correct answer.

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