Compound A, C$$_5$$H$$_{10}$$O$$_5$$, given a tetraacetate with AC$$_2$$O and oxidation of A with Br$$_2$$ - H$$_2$$O gives an acid, C$$_5$$H$$_{10}$$O$$_6$$. Reduction of A with HI gives isopentane. The possible structure of A is:

A

B

C

D