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We have the kinetic energy expressed in terms of momentum as $$K = \frac{p^2}{2m}$$.
If the momentum is increased by 20%, the new momentum is $$p' = 1.2\,p$$. The new kinetic energy is $$K' = \frac{(1.2\,p)^2}{2m} = \frac{1.44\,p^2}{2m} = 1.44\,K$$.
The percentage increase in kinetic energy is $$(1.44 - 1) \times 100\% = 44\%$$.
Hence, the correct answer is Option 3.
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