If 19 July 2000 was a Wednesday, then what would be the day of the week on 15 June 2012?

If the number of days between two dates is multiple of 7, they will have same day.

Number of odd days from 19 July 2000 to 31st Dec 2000 = (12+31+30+31+30+31)/7 = 165/7 = 4 days

Number of odd days in 2001, 2002, 2003, 2004, 2005....2011 will be 1, 1, 1, 2, 1, 1, 1, 2, 1, 1, 1, days respectively (2004 is leap year) = 13/7 = 6 days

The number of odd days from 1st Jan 2011 to 15 June 2011 is = 3+1+3+2+3+1 = 6 days

Therefore, total odd days = 4+6+6 = 16/7 = 2 days

If the day on 19 July 2000 was a Wednesday then on 15 June 2012 will be Friday.