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A water tank is fitted with four different taps as outlets. If the tank is full, it takes $$1\ \text{hour}$$ to empty the tank when the first tap alone is opened, it takesΒ $$2\ \text{hours}$$ to empty the tank when the second tap alone is opened, it takesΒ $$3\ \text{hours}$$ when the third tap alone is opened and $$4\ \text{hours}$$ to empty the tank when the fourth tap alone is opened. . When all the taps are opened simultaneously, the full tank will be emptied in
The combined emptying rate is $$1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}=\frac{25}{12}$$ tanks per hour. Hence the required time is $$\frac{12}{25}$$ hour. This is $$\frac{12}{25}\times 60=28.8$$ minutes, which lies between $$28$$ and $$29$$ minutes.
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