Kickstart Sale (25-28 April) 🥳 Crack CAT in the last 7 months with CAT courses by 5-time 100%iler 👉 Enroll here
Edit MetaData
If $$x^2 - x - 1 = 0$$, then the value of $$x^3 - 2x + 1$$ is
0
$$\frac{1 + \sqrt{5}}{2}$$
2
not uniquely determined
$$x^2 - x - 1 = 0$$
$$x^2 = 1 +Â x$$ Or $$x^2 - x = 1$$
$$= x^3 - 2x + 1 = x.x^2 - 2x + 1$$
$$=x.(1 + x) - 2x + 1$$
$$=x + x^2 - 2x + 1$$
$$=x^2 - x + 1$$
$$=1 + 1$$
= 2
Login to your Cracku account.
Enter Valid Email
Follow us on
Incase of any issue contact support@cracku.in
Boost your Prep!
Login and get one free mock test
Join cracku.in for Expert Guidance.