Question 48

Three of the following four letter-clusters are alike in a certain way and one is different. Find the odd one out.

Solution

$$SWYBE\longrightarrow\ S\ +\text{4=W, W +2=Y, Y+3=B, }B+3=E.$$ (using conversion table)

But, $$HKNQT\longrightarrow\ H+3=K,\ K+3=N,\ N+3=Q,\ Q+3=T.$$

$$CFILO\longrightarrow\ C+3=F,\ F+3=I,\ I+3=L,L+3=O.$$

$$QTWZC\longrightarrow\ Q+3=T,T+3=W,W+3=Z,Z+3=C.$$

Last three are in a pattern of three letter gap ,but letter in option does not follow it.

So, option A is correct choice.

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