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Match List I with List II
| List-I (Polymer) | List-II (Nature) |
|---|---|
A
![]() | I. Thermosetting polymer |
B
![]() | II. Fibers |
C
![]() | III. Elastomer |
D
![]() | IV. Thermoplastic polymer |
Polymer $$\mathrm{A}$$ represents:
$$\mathrm{Neoprene}$$
Neoprene is a synthetic rubber.
Rubbers possess weak intermolecular forces, allowing polymer chains to stretch easily.
Hence, neoprene is an:
$$\mathrm{Elastomer}$$
Thus:
$$\mathrm{A \rightarrow III}$$
Polymer $$\mathrm{B}$$ represents:
$$\mathrm{Nylon\ 6,6}$$
Nylon contains strong intermolecular hydrogen bonding between polymer chains.
This gives high tensile strength and close packing of chains.
Hence, nylon behaves as a:
$$\mathrm{Fiber}$$
Thus:
$$\mathrm{B \rightarrow II}$$
Polymer $$\mathrm{C}$$ represents:
$$\mathrm{Polyvinyl\ Chloride\ (PVC)}$$
PVC softens on heating and hardens on cooling without undergoing chemical change.
This is the characteristic property of:
$$\mathrm{Thermoplastic\ Polymers}$$
Thus:
$$\mathrm{C \rightarrow IV}$$
Polymer $$\mathrm{D}$$ represents:
$$\mathrm{Phenol\text{-}Formaldehyde\ Resin}$$
On heating, extensive cross-linking occurs, producing a rigid three-dimensional network.
Once formed, it cannot be remelted or reshaped.
Hence, it is a:
$$\mathrm{Thermosetting\ Polymer}$$
Thus:
$$\mathrm{D \rightarrow I}$$
Therefore, the correct matching is:
$$\mathrm{A\text{-}III,\ B\text{-}II,\ C\text{-}IV,\ D\text{-}I}$$
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