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Let f(x) be differentiable on the interval $$(0, \infty)$$ suh that f(1) = 1, and $$\lim_{t \rightarrow x}\frac{t^2 f(x) - x^2f(t)}{t-x} = 1$$ for each x > 0. Then f(x) is
$$\frac{1}{3x}+\frac{2x^2}{3}$$
$$\frac{-1}{3x}+\frac{4x^2}{3}$$
$$\frac{-1}{x}+\frac{2}{x^2}$$
$$\frac{1}{x}$$
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