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Chlorobenzene reacts with sodium hydroxide only under very harsh conditions because the $$\mathrm{C-Cl}$$ bond in aryl halides has partial double bond character due to resonance, making nucleophilic substitution difficult.
When chlorobenzene is fused with aqueous $$\mathrm{NaOH}$$ at high temperature and high pressure, it forms sodium phenoxide.
$$\mathrm{C_6H_5Cl + NaOH \xrightarrow[300\ atm]{623\ K} C_6H_5ONa + NaCl}$$
On subsequent acidification, sodium phenoxide is converted into phenol.
$$\mathrm{C_6H_5ONa + HCl \rightarrow C_6H_5OH + NaCl}$$
Therefore, the required reaction conditions for the conversion of chlorobenzene to sodium phenoxide are:
Hence, the correct answer is Option (D): $$623\ \mathrm{K},\ 300\ \mathrm{atm}$$.
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