The stable carbocation formed in the above reaction is:

The major product 'A' is Cumene (also known as Isopropylbenzene).

When benzene reacts with 1-chloropropane $$(\text{CH}_3\text{CH}_2\text{CH}_2\text{Cl})$$ in the presence of anhydrous $$\text{AlCl}_{3}$$, a carbocation rearrangement occurs.

Carbocation Formation: The Lewis acid $$(\text{AlCl}_{3})$$ abstracts the chloride ion, forming a primary carbocation: 

$$\text{CH}_3\text{CH}_2\text{CH}_2^+$$.

Rearrangement: A 1,2-hydride shift occurs to convert the unstable primary carbocation into a more stable secondary carbocation: 

$$\text{CH}_3\text{C}^+\text{HCH}_3$$ (isopropyl carbocation).

which is the most stable carbocation formed during this reaction.

Hence, Option C is Correct.