Letters of the word :
M A T H E I C S
M A T
Case 1 : 4 are different (all four words chosen are different, no repition)
= $$C^8_4\times4!=70\times24=1680$$
Case 2 : 2 alike + 2 different (out of the chosen four letters, two are same, rest two are chosen of the remaining seven)
= $$C^3_1\times C^7_2\times\frac{4!}{2!}$$
= $$3\times21\times12=756$$
Case 3 : 2 alike + 2 alike (four letters are chosen from M,A,T)
= $$C^3_2\times\frac{4!}{2!2!}=18$$
$$\therefore$$ Total number of ways = $$1680+756+18=2454$$
=> Ans - (B)
Create a FREE account and get: