Question 41

A ladder 25 metres long is placed against a wall with its foot 7 metres away from the foot of the wall. How far should the foot be drawn out so that the top of the ladder may come down by half the distance of the total distance if the foot is drawn out?

Solution

Distance between the top of ladder and foot of wall = $$\sqrt{25^2 - 7^2}$$ = 24 m. Let us assume that C is moved by a distance x m.

Using, Pythagoras theorem we can say that, 25^2 = 12^2 + (7+x)^2 => x = $$\sqrt{481}$$ - 7 = 14.93 m.

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