Question 40
The expression $$(a - b)^3 + (b - c)^3 + (c - a)^3$$ can be factorized as
Solution
If X+ Y+Z = 0 , then $$X^3+Y^3+Z^3=3XYZ$$
Let a-b = X, b-c = Y, c-a = Z
We can see that X+Y+Z=0
so $$(a - b)^3 + (b - c)^3 + (c - a)^3$$ = 3(a-b)(b-c)(c-a)
B is the correct answer.
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