If 'A' stands 'addition', B stands for 'division', C stands for 'subtraction' and D stands for 'multiplication, then what is the value of the following equation?
4 D (3 A 1) C 5 A (6 B 2) C 7
= 4 D (3 A 1) C 5 A (6 B 2) C 7
$$=4\times(3+1)-5+(\frac{\ 6\ \ }{2})-7$$
$$=4\times4-5+3-7$$
$$=16-5+3-7$$
=Â 7
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